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Home » army of the dead 2 - ECD Germany

army of the dead 2 - ECD Germany

📅 May 7, 2026 👤 scraface

May 07, 2026

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📌 Now substitute \( a+b \), \( a^2+b^2 \), and \( ab \) into the sum of cubes formula:

📌 Question:** A cartographer is designing a map transformation function \( T(x) = 3x^2 - 2x + 5 \). If \( x = g(y) = 2y + 1 \), find \( T(g(3)) \).

📌 First, find \( g(3) \):

📌 g(3) = 2(3) + 1 = 7

📌 Now substitute \( x = g(3) = 7 \) into \( T(x) \):

📌 T(7) = 3(7)^2 - 2(7) + 5

📌 3(7)^2 = 3 \times 49 = 147

📌 -2(7) = -14

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\frac{2x^4 + 2}{x^4 - 1} = 2 \cdot \frac{x^4 + 1}{x^4 - 1}
Let’s simplify $ x^4 + 1 $ and $ x^4 - 1 $. Since $ x + \frac{1}{x} =...
x^2 + \frac{1}{x^2} = 23 \Rightarrow x^4 + \frac{1}{x^4} = (x^2 + \fra...
x^4 + 1 = x^4 + \frac{1}{x^4} \cdot x^4 = x^4 + \frac{x^4}{x^4} = x^4...
Instead, observe:
\frac{x^2 + 1}{x^2 - 1} + \frac{x^2 - 1}{x^2 + 1} = y + \frac{1}{y} =...
Let’s compute this directly using the identity:
\frac{a + b}{a - b} + \frac{a - b}{a + b} = \frac{(a + b)^2 + (a - b)^...
\frac{2(x^2 + 1)}{x^2 - 1}
From earlier, $ x + \frac{1}{x} = 5 \Rightarrow x^2 + \frac{1}{x^2} =...

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