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\gcd(3^{15} - 1, 3^9 - 1) = 3^{\gcd(15,9)} - 1.
Now compute $\gcd(15,9) = 3$.
\gcd(3^{15} - 1, 3^9 - 1) = 3^3 - 1 = 27 - 1 = 26.

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