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📅 May 6, 2026 👤 scraface

May 06, 2026

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📌 A ball is thrown upward with an initial velocity of 20 m/s. Using \(h = -5t^2 + 20t\), find the maximum height reached.

📌 The height function is \(h(t) = -5t^2 + 20t\).

📌 The vertex (maximum) occurs at \(t = -\frac{b}{2a} = -\frac{20}{2 \times -5} = 2\) seconds.

📌 Substitute \(t = 2\) into the height equation: \(h(2) = -5(2)^2 + 20(2) = -20 + 40 = 20\) meters.

📌 #### 20**Question:

📌 Let \( x, y, z \) be positive real numbers. Find the minimum value of

📌 \frac{x + y}{x - y} + \frac{y + z}{y - z} + \frac{z + x}{z - x}

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