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Home » Never Slow Down Again: Master ConcurrentHashMap in Java with These Shocking Tricks! - ECD Germany

Never Slow Down Again: Master ConcurrentHashMap in Java with These Shocking Tricks! - ECD Germany

📅 May 4, 2026 👤 scraface

May 04, 2026

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📌 Set equal to $ 2t + 1 $:

📌 2at + (a + b) = 2t + 1.

📌 2a = 2 \Rightarrow a = 1, \quad a + b = 1 \Rightarrow 1 + b = 1 \Rightarrow b = 0.

📌 Thus, $ E(t) = t^2 $.

📌 Then $ E(10) = 10^2 = 100 $.

📌 Alternatively, recognize the recurrence as the discrete analog of derivative; sum telescoping:

📌 E(1) = E(0) + 1 = 1, \quad E(2) = 1 + (2\cdot1 + 1) = 1 + 3 = 4, \quad \text{etc.}

📌 So $ E(n) = \sum_{k=0}^{n-1} (2k + 1) = n^2 $, since sum of first $ n $ odd numbers is $ n^2 $.

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