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📅 May 5, 2026 👤 scraface

May 05, 2026

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📝 Recent Posts

\mathbf{v} \times \mathbf{a} = \begin{pmatrix} y(4) - z(-1) \\ z(2) -...
4y + z = 5 \\
2z - 4x = -6 \\
-x - 2y = -1
From the third equation: $x = 1 - 2y$.
2z - 4(1 - 2y) = -6 \Rightarrow 2z - 4 + 8y = -6 \Rightarrow 2z + 8y =...
Now solve the first and new second equation:
z + 4y = -1
\Rightarrow \text{Subtract: } 0 = 6 \Rightarrow \text{Contradiction}
This suggests no solution exists unless the given cross product is inc...

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