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📅 May 15, 2026 👤 scraface

May 15, 2026

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Increased area = 1,980 mÂ²
Let width of the path = x meters.
New dimensions = (50 + 2x) Ã (30 + 2x)
1,500 + 100x + 60x + 4xÂ² = 1,980
4xÂ² + 160x + 1,500 = 1,980
4xÂ² + 160x - 480 = 0
Solving the quadratic equation: x = 3
Solve for x: 3xÂ² - 12x + 9 = 0.
Divide the equation by 3: xÂ² - 4x + 3 = 0
Factorize: (x - 3)(x - 1) = 0

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