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Weightless Part 1 | Marconi Union

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Weightless Part 1 | Marconi Union
Weightless Part 1 | Marconi Union
Weightless Part 1 | Marconi Union
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Marconi Union - Weightless — Music - 𝓁𝑜𝓋𝑒 MAFF

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So we solve \( 9x^2 + 16y^2 = 144 \) in integers with \( |x| \leq 4 \), \( |y| \leq 3 \).
We try all integer \( x \) from \( -4 \) to \( 4 \), compute \( 9x^2 \), then \( 16y^2 = 144 - 9x^2 \), so \( y^2 = \frac{144 - 9x^2}{16} \), must be a perfect square and integer.
\( x = 0 \): \( y^2 = \frac{144}{16} = 9 \) → \( y = \pm 3 \) → valid

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