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where to watch green bay packers vs baltimore ravens - ECD Germany

📅 May 13, 2026 👤 scraface

May 13, 2026

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p(x) = \text{remainder of } p(x) \div (x^4 - 1) \quad \text{only if }...
But $ p(x) $ is cubic, so remainder $ r(x) = p(x) $, but only if $ x^4...
Wait: actually, **any** polynomial $ p(x) $ of degree less than 4 **is...
p(x) = 0 \cdot (x^4 - 1) + p(x)
So the remainder is **$ p(x) $** itself. But the problem asks for the...
But we are given four values, so we reconstruct $ p(x) $.
Let $ p(x) = ax^3 + bx^2 + cx + d $
Use the values:
$ p(0) = d = 2 $
$ p(1) = a + b + c + d = 5 \Rightarrow a + b + c = 3 $

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For a cycle of $ n $ nodes, there are exactly $ n $ edges.
Here, $ n = 12 $, so the number of unique communication pairs is $ 12...
Each pair corresponds to a direct communication link, and in a cycle,...
Thus, the total number of unique communication pairs is:
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